What is the domain of f(x)= 1/(\frac{x){x+1}} ?

The domain of f(x)= 1/(\frac{x){x+1}} is x 0

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domain of f(x)= 1/(\frac{x){x+1}}

domain

f (x) = \frac{1}{\frac{x}{x + 1}}

x < - 1 or - 1 < x < 0 or x > 0

Interval Notation

(- \infty, - 1) \cup (- 1, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 1

The function domain

x < - 1 or - 1 < x < 0 or x > 0

f (x) = 1

f (x) = 1 - 5 \cdot x \cdot e^{- x}

y = 3^{x} + 5

\frac{3 x - 4}{x - 2}

f (x) = \frac{1}{2 + x}

What is the domain of f(x)= 1/(\frac{x){x+1}} ?
The domain of f(x)= 1/(\frac{x){x+1}} is x<-1\lor-1<x<0\lor x>0