x=3+t,y=-t^2

Lösung

x = 3 + t, y = - t^{2}

3 - t^{2}

Schritte zur Lösung

Finde

x \circ y

gegeben

x = 3 + t, y = - t^{2}

x \circ y = (x) ((y) (t))

y = - t^{2}

= (x) (- t^{2})

(x) (- t^{2}) : 3 - t^{2}

= 3 - t^{2}

s l o p e y = 6

s l o p e y = 5

s l o p e x = 3

s l o p e in t erce pt 5 x - 4 y = 8

s l o p e y = 7