extreme f(x)=f(x)=xsqrt(x^2+4)

解答

极值点

f (x) = f (x) = x x^{2} + 4

无

求解步骤

f^{'} (x) = \frac{2 x ^{2} + 4}{x ^{2} + 4}

Find intervals:

无

无

e x t re m e f (x) = 2 x^{3} + 3 x^{2} - 120 x + 9

e x t re m e f (x) = x^{3} + 12 x^{2} - 27 x + 6, - 10 \leq x \leq 0

e x t re m e y = (2 x^{2} - 1)^{2}

e x t re m e f (x) = \frac{6}{- 4 x + 2}

e x t re m e f (y) = x^{y + 1}