What is the domain of f(x)=\sqrt[3]{x^3} ?

The domain of f(x)=\sqrt[3]{x^3} is -infinity <x<infinity

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domain of f(x)=\sqrt[3]{x^3}

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = e^{- x^{2}}

\frac{1}{x + 8}

f (x) = x^{3} - 6 x^{2} + 3 x + 10

f (x) = 3 t^{5} - 5 t^{3}

f (x) = 6 x^{3} - 1

What is the domain of f(x)=\sqrt[3]{x^3} ?
The domain of f(x)=\sqrt[3]{x^3} is -infinity <x<infinity