extreme f(x)=39+6x+(54)/x

Lösung

extrempunkte

f (x) = 39 + 6 x + \frac{54}{x}

Maximum (- 3, 3), Minimum (3, 75)

Schritte zur Lösung

f^{'} (x) = - \frac{54}{x ^{2}} + 6

Intervalle finden:

Ansteigend

: - \infty < x < - 3,

Absteigend

: - 3 < x < 0,

Absteigend

: 0 < x < 3,

Ansteigend

: 3 < x < \infty

Stecke

x = - 3

39 + 6 x + \frac{54}{x} : 3

Maximum (- 3, 3)

Stecke

x = 3

39 + 6 x + \frac{54}{x} : 75

Minimum (3, 75)

Maximum (- 3, 3), Minimum (3, 75)

e x t re m e \frac{e ^{x}}{x ^{4}}

e x t re m e F (x, y) = x^{2} + x y + y^{2} + 3 x - 3 y + 4

e x t re m e f (x, y) = 6 - 2 x + 4 y - x^{2} - 4 y^{2}

e x t re m e f (x) = (4 x - 1)^{2}

e x t re m e f (x) = 5 x^{2} - 10 x + 2, - 4 \leq x \leq 2