What is the amplitude of 2sin((2piθ)/5) ?

The amplitude of 2sin((2piθ)/5) is 2

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amplitude of 2sin((2piθ)/5)

amplitude

2 sin (\frac{2 π θ}{5})

2

Solution steps

f (x) = 2 sin (\frac{2 π θ}{5}), A = 2

Therefore, the amplitude |A| is

2

2

f (x) = \frac{x - 2}{x ^{2} + 4}

f (x) = \frac{4}{x - 3}

\frac{1}{x + 4} - 2

12 x + 5 y = - 13

\frac{x ^{2} + 2 x - 3}{x - 2}