extreme (0.5x^2+4x-10)/(x-6)

Lösung

extrempunkte

\frac{0.5 x ^{2} + 4 x - 10}{x - 6}

Maximum (- 2, 2), Minimum (14, 18)

Schritte zur Lösung

f^{'} (x) = \frac{0.5 x ^{2} - 6 x - 14}{( x - 6 ) ^{2}}

Intervalle finden:

Ansteigend

: - \infty < x < - 2,

Absteigend

: - 2 < x < 6,

Absteigend

: 6 < x < 14,

Ansteigend

: 14 < x < \infty

Stecke

x = - 2

\frac{0.5 x ^{2} + 4 x - 10}{x - 6} : 2

Maximum (- 2, 2)

Stecke

x = 14

\frac{0.5 x ^{2} + 4 x - 10}{x - 6} : 18

Minimum (14, 18)

Maximum (- 2, 2), Minimum (14, 18)

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