What is the inverse of f(x)=4x^2-3 ?

The inverse of f(x)=4x^2-3 is (sqrt(x+3))/2 ,-(sqrt(x+3))/2

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inverse of f(x)=4x^2-3

inverse

f (x) = 4 x^{2} - 3

\frac{x + 3}{2}, - \frac{x + 3}{2}

Solution steps

y = 4 x^{2} - 3

Replace

x

with

y

x = 4 y^{2} - 3

Solve for

y, x = 4 y^{2} - 3

\frac{x + 3}{2}, - \frac{x + 3}{2}

f (x) = \frac{3}{x - 2}

f (x) = 3 e^{x^{2} - 4 x}

f (x) = 2 + x - 1

\frac{x}{x ^{2} + 1}

f (x) = ∣ x - 3 ∣

What is the inverse of f(x)=4x^2-3 ?
The inverse of f(x)=4x^2-3 is (sqrt(x+3))/2 ,-(sqrt(x+3))/2