What is the critical sin^2(16x) ?

The critical sin^2(16x) is x= pi/(16)n,x= pi/(32)+pi/(16)n

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critical sin^2(16x)

critical points

sin^{2} (16 x)

x = \frac{π}{16} n, x = \frac{π}{32} + \frac{π}{16} n

Solution steps

sin^{2} (16 x)

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{π}{16} n, x = \frac{π}{32} + \frac{π}{16} n

Identify critical points not in

f (x)

domain

Domain of

sin^{2} (16 x) : - \infty < x < \infty

All critical points are in domain

x = \frac{π}{16} n, x = \frac{π}{32} + \frac{π}{16} n

\frac{x ^{2} - 2 x - 2}{x - 3}

2 x + 5 y = 8

f (x) = 140 \cdot 1. 6^{x}

y = cos (2 x)

- 4 x + 2 y = 20

What is the critical sin^2(16x) ?
The critical sin^2(16x) is x= pi/(16)n,x= pi/(32)+pi/(16)n