What is the domain of f(x)= 1/(2x^2+3) ?

The domain of f(x)= 1/(2x^2+3) is -infinity <x<infinity

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domain of f(x)= 1/(2x^2+3)

domain

f (x) = \frac{1}{2 x ^{2} + 3}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = 4 x + 5

f (x) = 5

9 x + \frac{7}{x}

f (x) = \frac{x + 2}{x ^{2} + 7 x + 10}

\frac{x}{4} + \frac{17}{4}

What is the domain of f(x)= 1/(2x^2+3) ?
The domain of f(x)= 1/(2x^2+3) is -infinity <x<infinity