What is the domain of f(x)=(x+5)/(x^2-1) ?

The domain of f(x)=(x+5)/(x^2-1) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x+5)/(x^2-1)

domain

f (x) = \frac{x + 5}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = - \frac{2}{5} (x - 5)^{2} + 10

\frac{7 x - 1}{4 x ^{2} - 27 x - 81}

\frac{1}{6} x^{2} - 1

\frac{x ^{2}}{x ^{2} - 1}

y = 2 x - 6

What is the domain of f(x)=(x+5)/(x^2-1) ?
The domain of f(x)=(x+5)/(x^2-1) is x<-1\lor-1<x<1\lor x>1