extreme-(2e^x)/(-4x-1)

Lösung

extrempunkte

- \frac{2 e ^{x}}{- 4 x - 1}

Minimum (\frac{3}{4}, \frac{e ^{\frac{3}{4}}}{2})

Schritte zur Lösung

f^{'} (x) = - \frac{2 ( - 4 e ^{x} x + 3 e ^{x} )}{( - 4 x - 1 ) ^{2}}

Intervalle finden:

Absteigend

: - \infty < x < - \frac{1}{4},

Absteigend

: - \frac{1}{4} < x < \frac{3}{4},

Ansteigend

: \frac{3}{4} < x < \infty

Stecke

x = \frac{3}{4}

- \frac{2 e ^{x}}{- 4 x - 1} : \frac{e ^{\frac{3}{4}}}{2}

Minimum (\frac{3}{4}, \frac{e ^{\frac{3}{4}}}{2})

e x t re m e f (9) = \frac{t}{t - 4}

e x t re m e x^{2} + \frac{405000}{x}

e x t re m e \frac{2 x ^{2} - 14 x + 24}{x ^{2} + 6 x + 40}

e x t re m e f (x) = x (5 - x) (8 - x), 0 < x < 5

e x t re m e f (x) = \frac{( x ^{2} + 121 )}{2 x}