What is the inverse of y=log_{3}(x^4) ?

The inverse of y=log_{3}(x^4) is sqrt(3^{x/2)},-sqrt(3^{x/2)}

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inverse of y=log_{3}(x^4)

inverse

y = lo g_{3} (x^{4})

3^{\frac{x}{2}}, - 3^{\frac{x}{2}}

Solution steps

y = lo g_{3} (x^{4})

Replace

x

with

y

x = lo g_{3} (y^{4})

Solve for

y, x = lo g_{3} (y^{4})

3^{\frac{x}{2}}, - 3^{\frac{x}{2}}

lo g_{6} (x) - 6

f (x) = 0

f (x) = \frac{x - 2}{x - 1}

8 x + y = 3

f (x) = \frac{\frac{x}{x + 5}}{\frac{x}{x + 5} + 5}

What is the inverse of y=log_{3}(x^4) ?
The inverse of y=log_{3}(x^4) is sqrt(3^{x/2)},-sqrt(3^{x/2)}