What is the domain of f(x)=sqrt(x^3-x) ?

The domain of f(x)=sqrt(x^3-x) is -1 = 1

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domain of f(x)=sqrt(x^3-x)

domain

f (x) = x^{3} - x

- 1 \leq x \leq 0 or x \geq 1

Interval Notation

[- 1, 0] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 0 or x \geq 1

The function domain

- 1 \leq x \leq 0 or x \geq 1

(5, - 6), (8, - 9)

f (x) = x + 12

f (x) = \frac{1}{x + 4}

\frac{2 x + 6}{- 6 x + 3}

f (x) = \frac{2 x + 1}{x - 5}

What is the domain of f(x)=sqrt(x^3-x) ?
The domain of f(x)=sqrt(x^3-x) is -1<= x<= 0\lor x>= 1