What is the domain of \sqrt[3]{\sqrt[3]{x}} ?

The domain of \sqrt[3]{\sqrt[3]{x}} is -infinity <x<infinity

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domain of \sqrt[3]{\sqrt[3]{x}}

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = x^{2} + 2 x - 1

f (x) = 49 x + 72

f (x) = \frac{x ^{2} - 11 x - 12}{x + 4}

f (x) = x^{2} + 8 x + 1

y = - 2 x

What is the domain of \sqrt[3]{\sqrt[3]{x}} ?
The domain of \sqrt[3]{\sqrt[3]{x}} is -infinity <x<infinity