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受欢迎的函数 >

extreme y=ln(x^2)+8x+24

解答

极值点

y = ln (x^{2}) + 8 x + 24

解答

极大值 (- \frac{1}{4}, - 4 ln (2) + 22)

求解步骤

f^{'} (x) = \frac{2}{x} + 8

Find intervals:

递增

: - \infty < x < - \frac{1}{4},

递减

: - \frac{1}{4} < x < 0,

递增

: 0 < x < \infty

将

x = - \frac{1}{4}

代入

ln (x^{2}) + 8 x + 24 : - 4 ln (2) + 22

极大值 (- \frac{1}{4}, - 4 ln (2) + 22)

作图

流行的例子

extreme f(x)=x^3-2x^2-4x+8,-1<= x<= 0

e x t re m e f (x) = x^{3} - 2 x^{2} - 4 x + 8, - 1 \leq x \leq 0

extreme f(x)= 1/(3x^3+2x^2+3x)

e x t re m e f (x) = \frac{1}{3 x ^{3} + 2 x ^{2} + 3 x}

extreme T(x,y)=(|x|,2y)

e x t re m e T (x, y) = (∣ x ∣, 2 y)

extreme f(x)=x^3+6x^2+9x-3

e x t re m e f (x) = x^{3} + 6 x^{2} + 9 x - 3

extreme f(x)=-2x^3+6x^2-5

e x t re m e f (x) = - 2 x^{3} + 6 x^{2} - 5