What is the perpendicular 5x+3y=3 ?

The perpendicular 5x+3y=3 is y= 3/5 x+b

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perpendicular 5x+3y=3

perpendicular

5 x + 3 y = 3

y = \frac{3}{5} x + b

Solution steps

Find the slope of

5 x + 3 y = 3 : m = - \frac{5}{3}

Compute the slope of the perpendicular line:

m_{p} = \frac{3}{5}

Line with slope m=

\frac{3}{5} : y = \frac{3}{5} x + b

y = \frac{3}{5} x + b

f (x) = \frac{1}{x + 1}

\frac{3}{4}

f (x) = - x^{6}

f (x) = \frac{5 x - 10}{- 2 x ^{2} - 6 x + 20}

f (x) = \frac{2}{9} x + \frac{8}{9}