y<= 2y<8

The solution to y<= 2y<8 is 0<= y<4

Solution

y \leq 2 y < 8

0 \leq y < 4

Interval Notation

[0, 4)

Solution steps

y \leq 2 y < 8

a \leq u < b

then

a \leq u and u < b

y \leq 2 y and 2 y < 8

y \leq 2 y : y \geq 0

2 y < 8 : y < 4

Combine the intervals

y \geq 0 and y < 4

Merge Overlapping Intervals

0 \leq y < 4

sin (5 x)

f (x) = \frac{2 x}{x + 5}

f (x) = \frac{x ^{2} - x - 4}{x - 3}

(1, 3), (- 1, 2)