What is the inverse of f(x)=x^{1/4}-3 ?

The inverse of f(x)=x^{1/4}-3 is x^4+12x^3+54x^2+108x+81

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inverse of f(x)=x^{1/4}-3

inverse

f (x) = x^{\frac{1}{4}} - 3

x^{4} + 12 x^{3} + 54 x^{2} + 108 x + 81

Solution steps

y = x^{\frac{1}{4}} - 3

Replace

x

with

y

x = y^{\frac{1}{4}} - 3

Solve for

y, x = y^{\frac{1}{4}} - 3

x^{4} + 12 x^{3} + 54 x^{2} + 108 x + 81

f (x) = lo g_{2} (x + 2)

f (x) = \frac{( x + 1 ) ^{\frac{1}{3}}}{x ^{2} - 5 x + 4}

- 6 \cdot 3 \cdot x + 6 + 2 \cdot 3 \cdot π

f (x) = - \frac{3}{2} tan (x - \frac{π}{6})

(- 3.5) (4.4)

What is the inverse of f(x)=x^{1/4}-3 ?
The inverse of f(x)=x^{1/4}-3 is x^4+12x^3+54x^2+108x+81