What is the domain of f(x)=(8x+1)/(x^2-4) ?

The domain of f(x)=(8x+1)/(x^2-4) is x 2

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domain of f(x)=(8x+1)/(x^2-4)

domain

f (x) = \frac{8 x + 1}{x ^{2} - 4}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

y = - \frac{1}{4} x + 3 (4.1)

f (x) = \frac{2}{x} - 5

- 3 x + 5

f (x) = 3 x^{3} - 36 x - 9

f (x) = x^{2} + x

What is the domain of f(x)=(8x+1)/(x^2-4) ?
The domain of f(x)=(8x+1)/(x^2-4) is x<-2\lor-2<x<2\lor x>2