What is the range of \sqrt[3]{x+1}+3 ?

The range of \sqrt[3]{x+1}+3 is -infinity <f(x)<infinity

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range of \sqrt[3]{x+1}+3

range

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

Inverse of

x^{3} - 9 x^{2} + 27 x - 28

Find the domain of each inverse function

Domain of

x^{3} - 9 x^{2} + 27 x - 28 : - \infty < x < \infty

Combine the intervals

- \infty < f (x) < \infty

y = x^{2} - 3 x + 3

y = - 5 x + 2

y - 6 = 3 (x - 1)

y = \frac{5}{( 1 - 2 x ) ^{2}}

f (x) = - 3 x

What is the range of \sqrt[3]{x+1}+3 ?
The range of \sqrt[3]{x+1}+3 is -infinity <f(x)<infinity