What is the domain of f(x)=(x^2)/(2x-7) ?

The domain of f(x)=(x^2)/(2x-7) is x 7/2

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domain of f(x)=(x^2)/(2x-7)

domain

f (x) = \frac{x ^{2}}{2 x - 7}

x < \frac{7}{2} or x > \frac{7}{2}

Interval Notation

(- \infty, \frac{7}{2}) \cup (\frac{7}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{7}{2}

The function domain

x < \frac{7}{2} or x > \frac{7}{2}

f (x) = \frac{( x + 2 )}{( x - 2 )}

- x^{2} + 8 x - 7

f (x) = lo g_{3} (x^{2})

\frac{1 + sin ( y )}{1 - sin ( y )}

\frac{1}{3} x - 1

What is the domain of f(x)=(x^2)/(2x-7) ?
The domain of f(x)=(x^2)/(2x-7) is x< 7/2 \lor x> 7/2