What is the domain of f(x)=(sqrt(1-x^2))/x ?

The domain of f(x)=(sqrt(1-x^2))/x is -1<= x<0\lor 0<x<= 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(sqrt(1-x^2))/x

domain

f (x) = \frac{1 - x ^{2}}{x}

- 1 \leq x < 0 or 0 < x \leq 1

Interval Notation

[- 1, 0) \cup (0, 1]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 \leq x < 0 or 0 < x \leq 1

- 2 x^{3} + 36 x^{2}

f (x) = - 4 x

y = - 7 x + 2

\frac{x ^{2} + x - 12}{x - 3}

What is the domain of f(x)=(sqrt(1-x^2))/x ?
The domain of f(x)=(sqrt(1-x^2))/x is -1<= x<0\lor 0<x<= 1