What is the extreme f(x)=x^3-x^2-x+9 ?

The extreme f(x)=x^3-x^2-x+9 is Maximum(-1/3 , 248/27),Minimum(1,8)

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extreme f(x)=x^3-x^2-x+9

extreme points

f (x) = x^{3} - x^{2} - x + 9

Maximum (- \frac{1}{3}, \frac{248}{27}), Minimum (1, 8)

Solution steps

f^{'} (x) = 3 x^{2} - 2 x - 1

Find intervals:

Increasing

: - \infty < x < - \frac{1}{3},

Decreasing

: - \frac{1}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{1}{3}

into

x^{3} - x^{2} - x + 9 : \frac{248}{27}

Maximum (- \frac{1}{3}, \frac{248}{27})

Plug

x = 1

into

x^{3} - x^{2} - x + 9 : 8

Minimum (1, 8)

Maximum (- \frac{1}{3}, \frac{248}{27}), Minimum (1, 8)

(1, 5), (7, 13)

f (x) = (x^{2} - 6 x)^{\frac{1}{4}}

\frac{x ^{3} - x ^{2} - 2 x}{- 3 x ^{2} + 27}

(2, 1), (5, 7)

m = \infty, (3, 2)

What is the extreme f(x)=x^3-x^2-x+9 ?
The extreme f(x)=x^3-x^2-x+9 is Maximum(-1/3 , 248/27),Minimum(1,8)