en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

midpoint (-2,1),(-4,-2)

Solution

midpoint

(- 2, 1), (- 4, - 2)

Solution

(- 3, - \frac{1}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 2, 1), (x_{2}, y_{2}) = (- 4, - 2)

= (\frac{- 4 - 2}{2}, \frac{- 2 + 1}{2})

Refine

= (- 3, - \frac{1}{2})

Popular Examples

asymptotes of f(x)=(x^3-27)/(x^2+2x-15)asymptotes

f (x) = \frac{x ^{3} - 27}{x ^{2} + 2 x - 15}

parity f(x)=|x-2|parity

f (x) = ∣ x - 2 ∣

domain of f(x)=x^2+y^2=16 domain

f (x) = x^{2} + y^{2} = 16

inverse of f(x)=log_{2}(x+6)inverse

f (x) = lo g_{2} (x + 6)

intercepts of y=x^2-6x+3 intercepts

y = x^{2} - 6 x + 3

Frequently Asked Questions (FAQ)

What is the midpoint (-2,1),(-4,-2) ?
The midpoint (-2,1),(-4,-2) is (-3,-1/2)