What is the domain of f(x)=(sqrt(9+x))/(4-x) ?

The domain of f(x)=(sqrt(9+x))/(4-x) is -9 4

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domain of f(x)=(sqrt(9+x))/(4-x)

domain

f (x) = \frac{9 + x}{4 - x}

- 9 \leq x < 4 or x > 4

Interval Notation

[- 9, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

- 9 \leq x < 4 or x > 4

\frac{3 x}{x - 1}

f (x) = \frac{x + 6}{x ^{2} - 3 x - 4}

f (x) = 0.2 (x - 2) (x + 1) (x - 5)

(- 3, 4), (0, - 3)

f (x) = 3 x x

What is the domain of f(x)=(sqrt(9+x))/(4-x) ?
The domain of f(x)=(sqrt(9+x))/(4-x) is -9<= x<4\lor x>4