What is the domain of f(x)=(x^4)/(x^2+x-42) ?

The domain of f(x)=(x^4)/(x^2+x-42) is x 6

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domain of f(x)=(x^4)/(x^2+x-42)

domain

f (x) = \frac{x ^{4}}{x ^{2} + x - 42}

x < - 7 or - 7 < x < 6 or x > 6

Interval Notation

(- \infty, - 7) \cup (- 7, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 6, x = - 7

The function domain

x < - 7 or - 7 < x < 6 or x > 6

\frac{x ^{2} - 4}{x ^{2} - 5 x + 6}

(x - 4)^{2} - 1

f (x) = x^{2} - 2

f (x) = \frac{3 x x}{8}

f (x) = - x - 4

What is the domain of f(x)=(x^4)/(x^2+x-42) ?
The domain of f(x)=(x^4)/(x^2+x-42) is x<-7\lor-7<x<6\lor x>6