What is the critical f(x)= 1/2 x^2+4x+5 ?

The critical f(x)= 1/2 x^2+4x+5 is x=-4

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critical f(x)= 1/2 x^2+4x+5

critical points

f (x) = \frac{1}{2} x^{2} + 4 x + 5

x = - 4

Solution steps

\frac{1}{2} x^{2} + 4 x + 5

Find where

f^{'} (x)

is equal to zero or undefined

x = - 4

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{2} x^{2} + 4 x + 5 : - \infty < x < \infty

All critical points are in domain

x = - 4

f (x) = 3 x - 6

4 - x

2 x^{2} + 4 x - 1

2 x + y = - 5

f (x) = 4 x - 7

What is the critical f(x)= 1/2 x^2+4x+5 ?
The critical f(x)= 1/2 x^2+4x+5 is x=-4