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Popular >

extreme f(x)=ln(3-2x^2)

Solution

extreme points

f (x) = ln (3 - 2 x^{2})

Solution

Maximum (0, ln (3))

Solution steps

f^{'} (x) = - \frac{4 x}{3 - 2 x ^{2}}

Find intervals:

Increasing

: - \frac{3}{2} < x < 0,

Decreasing

: 0 < x < \frac{3}{2}

Plug

x = 0

into

ln (3 - 2 x^{2}) : ln (3)

Maximum (0, ln (3))

Popular Examples

inverse of f(x)=x^2+3x-4 inverse

f (x) = x^{2} + 3 x - 4

parallel x+2y=6,(1,-3)parallel

x + 2 y = 6, (1, - 3)

critical f(x)=(x^2-9)/(x^2+6)critical points

f (x) = \frac{x ^{2} - 9}{x ^{2} + 6}

intercepts of 3*2^{x-4}-5 intercepts

3 \cdot 2^{x - 4} - 5

domain of f(x)=((1-x))/(2x-1)domain

f (x) = \frac{( 1 - x )}{2 x - 1}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=ln(3-2x^2) ?
The extreme f(x)=ln(3-2x^2) is Maximum(0,ln(3))