What is the extreme f(x)=3x^3-36x-8 ?

The extreme f(x)=3x^3-36x-8 is Maximum(-2,40),Minimum(2,-56)

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extreme f(x)=3x^3-36x-8

extreme points

f (x) = 3 x^{3} - 36 x - 8

Maximum (- 2, 40), Minimum (2, - 56)

Solution steps

f^{'} (x) = 9 x^{2} - 36

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

3 x^{3} - 36 x - 8 : 40

Maximum (- 2, 40)

Plug

x = 2

into

3 x^{3} - 36 x - 8 : - 56

Minimum (2, - 56)

Maximum (- 2, 40), Minimum (2, - 56)

f (x) = \frac{- 6}{9 - x}

f (x) = 7 x^{2} + 9

f (x) = 3^{x} + 2

m = \frac{8}{3}, (13, 5)

f (x) = x^{3} - 11 x^{2} + 24 x

What is the extreme f(x)=3x^3-36x-8 ?
The extreme f(x)=3x^3-36x-8 is Maximum(-2,40),Minimum(2,-56)