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Popular >

midpoint (4,-7),(12,-1)

Solution

midpoint

(4, - 7), (12, - 1)

Solution

(8, - 4)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (4, - 7), (x_{2}, y_{2}) = (12, - 1)

= (\frac{12 + 4}{2}, \frac{- 1 - 7}{2})

Refine

= (8, - 4)

Popular Examples

domain of-x^2+16x-62 domain

- x^{2} + 16 x - 62

asymptotes of y= 2/(x+2)+1 asymptotes

y = \frac{2}{x + 2} + 1

parity f(x)=x^2+6 parity

f (x) = x^{2} + 6

extreme f(x)=x^3-2x^2-4x+7 extreme points

f (x) = x^{3} - 2 x^{2} - 4 x + 7

asymptotes of sqrt(x^2+x-6)asymptotes

x^{2} + x - 6

Frequently Asked Questions (FAQ)

What is the midpoint (4,-7),(12,-1) ?
The midpoint (4,-7),(12,-1) is (8,-4)