What is the domain of f(x)= 9/(25-x^2) ?

The domain of f(x)= 9/(25-x^2) is x 5

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domain of f(x)= 9/(25-x^2)

domain

f (x) = \frac{9}{25 - x ^{2}}

x < - 5 or - 5 < x < 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (- 5, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 5

The function domain

x < - 5 or - 5 < x < 5 or x > 5

2 t

f (x) = x - 2

f (x) = \frac{3}{2 x - 6} + 7

(\frac{x}{2 x ^{2} - 5}) (x)

x^{2} + 2 x - 2

What is the domain of f(x)= 9/(25-x^2) ?
The domain of f(x)= 9/(25-x^2) is x<-5\lor-5<x<5\lor x>5