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Popular >

distance (8,-3),(4,-7)

Solution

distance

(8, - 3), (4, - 7)

Solution

42

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(8, - 3)

and

(4, - 7)

is

= (4 - 8)^{2} + (- 7 - (- 3))^{2}

Simplify

= 42

Popular Examples

domain of (2x-4)/(x^2+x-2)domain

\frac{2 x - 4}{x ^{2} + x - 2}

asymptotes of f(x)=(2x+3)/(x+1)asymptotes

f (x) = \frac{2 x + 3}{x + 1}

range of x^2-2x+1 range

x^{2} - 2 x + 1

domain of f(x)=x^3+4x^2 domain

f (x) = x^{3} + 4 x^{2}

domain of f(x)=(x-3)/x domain

f (x) = \frac{x - 3}{x}

Frequently Asked Questions (FAQ)

What is the distance (8,-3),(4,-7) ?
The distance (8,-3),(4,-7) is 4sqrt(2)