What is the inverse of f(x)=0.6x^2-1.5x+1 ?

The inverse of f(x)=0.6x^2-1.5x+1 is (15+sqrt(240x-15))/(12),(15-sqrt(240x-15))/(12)

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inverse of f(x)=0.6x^2-1.5x+1

inverse

f (x) = 0.6 x^{2} - 1.5 x + 1

\frac{15 + 240 x - 15}{12}, \frac{15 - 240 x - 15}{12}

Solution steps

y = 0.6 x^{2} - 1.5 x + 1

Replace

x

with

y

x = 0.6 y^{2} - 1.5 y + 1

Solve for

y, x = 0.6 y^{2} - 1.5 y + 1

\frac{15 + 240 x - 15}{12}, \frac{15 - 240 x - 15}{12}

f (x) = \frac{( x + 1 )}{( x + 7 )}

f (x) = x^{2} + 1

y = x^{3} - 2

(x, - 2), (- 5, - 5)

(\frac{1}{2}, 10), (0, \frac{- 1}{5})

What is the inverse of f(x)=0.6x^2-1.5x+1 ?
The inverse of f(x)=0.6x^2-1.5x+1 is (15+sqrt(240x-15))/(12),(15-sqrt(240x-15))/(12)