What is the critical f(x)=x^2-4x+7 ?

The critical f(x)=x^2-4x+7 is x=2

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critical f(x)=x^2-4x+7

critical points

f (x) = x^{2} - 4 x + 7

x = 2

Solution steps

x^{2} - 4 x + 7

Find where

f^{'} (x)

is equal to zero or undefined

x = 2

Identify critical points not in

f (x)

domain

Domain of

x^{2} - 4 x + 7 : - \infty < x < \infty

All critical points are in domain

x = 2

(3, 5), (11, 8)

f (x) = 2 x^{4} - x^{3} + 6 x^{2}

3 x - 4 y = 10

y = \frac{2 x}{3} + (x + 1)^{\frac{2}{3}}

(- 6, 1), (2, - 5)