What is the domain of sqrt(3-x)+sqrt(x^2-4) ?

The domain of sqrt(3-x)+sqrt(x^2-4) is x<=-2\lor 2<= x<= 3

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domain of sqrt(3-x)+sqrt(x^2-4)

domain

3 - x + x^{2} - 4

x \leq - 2 or 2 \leq x \leq 3

Interval Notation

(- \infty, - 2] \cup [2, 3]

Solution steps

Find non-negative values for radicals:

x \leq - 2 or 2 \leq x \leq 3

The function domain

x \leq - 2 or 2 \leq x \leq 3

\frac{2 x ^{2}}{3 x + 2}

g (x) = \frac{- x - 2}{x + 4}

f (x) = \frac{x + 5}{x + 9}

f (x) = \frac{10 x + 7}{7 x - 4}

f (x) = - \frac{2}{3} x - 4

What is the domain of sqrt(3-x)+sqrt(x^2-4) ?
The domain of sqrt(3-x)+sqrt(x^2-4) is x<=-2\lor 2<= x<= 3