What is the inverse of f(x)=((e^x-e^{-x}))/2 ?

The inverse of f(x)=((e^x-e^{-x}))/2 is ln(x+sqrt(x^2+1)),ln(x-sqrt(x^2+1))

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inverse of f(x)=((e^x-e^{-x}))/2

inverse

f (x) = \frac{( e ^{x} - e ^{- x} )}{2}

ln (x + x^{2} + 1), ln (x - x^{2} + 1)

Solution steps

y = \frac{e ^{x} - e ^{- x}}{2}

Replace

x

with

y

x = \frac{e ^{y} - e ^{- y}}{2}

Solve for

y, x = \frac{e ^{y} - e ^{- y}}{2}

ln (x + x^{2} + 1), ln (x - x^{2} + 1)

f (x) = - x^{2} + 3 x + 5

- 1

(c, d), (r, s)

f (x) = 2 x (x + 5)^{2}

\frac{1}{- x ^{2} + 2 x + 3}

What is the inverse of f(x)=((e^x-e^{-x}))/2 ?
The inverse of f(x)=((e^x-e^{-x}))/2 is ln(x+sqrt(x^2+1)),ln(x-sqrt(x^2+1))