变换 2/3 cos(2(θ/3-pi))+1/2

解答

变换

\frac{2}{3} cos (2 (\frac{θ}{3} - π)) + \frac{1}{2}

相位 : 3 π, 垂直 : \frac{1}{2}

求解步骤

f (x) = \frac{2}{3} cos (2 (\frac{θ}{3} - π)) + \frac{1}{2}

g (B x - C) = cos (2 (\frac{θ}{3} - π)), B = \frac{2}{3}, C = 2 π, D = \frac{1}{2}

因此，相位变换

\frac{C}{B}

为

\frac{2 π}{\frac{2}{3}}

3 π

垂直变换

D

为

\frac{1}{2}

\frac{1}{2}

d i s t an ce (- 1, \frac{19}{2}), (- 9, 11)

y = 3 x - 1

e x t re m e f (x) = - 32 t + 40

l in e (12, 3), (3, 12)

in t erce pt s cot (x + \frac{7 π}{36})