(\partial)/(\partial y)(1-y^3)

Lösung

\frac{\partial}{\partial y} (1 - y^{3})

- 3 y^{2}

Schritte zur Lösung

\frac{\partial}{\partial y} (1 - y^{3})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (1) - \frac{\partial}{\partial y} (y^{3})

\frac{\partial}{\partial y} (1) = 0

\frac{\partial}{\partial y} (y^{3}) = 3 y^{2}

= 0 - 3 y^{2}

Vereinfache

= - 3 y^{2}

\frac{d y}{d x} = \frac{1 + x}{y}

x \to 0 lim (\frac{7}{x ^{2} + x} - \frac{7}{x})

\frac{\partial}{\partial x} (\frac{x y}{x + 1})

in v erse l a pl a ce \frac{( s + 2 )}{( s + 1 ) ^{2}}

\frac{\partial}{\partial z} (x yz + x y^{5} + y z^{5} + z x^{5})