integral from 1/2 to 3/4 of 1/(u^2)

Lösung

\int_{\frac{1}{2}}^{\frac{3}{4}} \frac{1}{u ^{2}} d u

\frac{2}{3}

Dezimale

0.66666 \dots

Schritte zur Lösung

\int_{\frac{1}{2}}^{\frac{3}{4}} \frac{1}{u ^{2}} d u

Wende die Potenzregel an

= [- \frac{1}{u}]_{\frac{1}{2}}^{\frac{3}{4}}

Berechne die Grenzen:

\frac{2}{3}

= \frac{2}{3}

\int_{- 1}^{3} 3 x^{2} + 4 x d x

d er i v a t i v e y = arcsec (x^{2} + 1)

p a r i t y y = ln (x^{3} - 2 x^{2} + 2)

x \to \infty lim (\frac{2}{x} + 1)

\frac{\partial}{\partial x} (x y)