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Beliebt Rechnen >

y^'=(x+y-3)^2,y(0)=0

Lösung

y^{^{'}} = (x + y - 3)^{2}, y (0) = 0

Lösung

y = tan (x - 1.24904 \dots + πn) - x + 3

Schritte zur Lösung

y^{'} (x) = (x + y - 3)^{2}

Solve using substitution:

y = tan (x - 1.24904 \dots + πn) - x + 3

y = tan (x - 1.24904 \dots + πn) - x + 3

Graph

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