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Beliebt Rechnen >

y^'=(x+y-2)^2,y(0)=0

Lösung

y^{^{'}} = (x + y - 2)^{2}, y (0) = 0

Lösung

y = tan (x - 1.10714 \dots + πn) - x + 2

Schritte zur Lösung

y^{'} (x) = (x + y - 2)^{2}

Solve using substitution:

y = tan (x - 1.10714 \dots + πn) - x + 2

y = tan (x - 1.10714 \dots + πn) - x + 2

Graph

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