What is the solution for (dN)/(dt)+N=Nte^{(t+2)} ?

The solution for (dN)/(dt)+N=Nte^{(t+2)} is N=e^{e^2(e^tt-e^t)-t+c_{1}}

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(dN)/(dt)+N=Nte^{(t+2)}

\frac{d N}{d t} + N = Nt e^{(t + 2)}

N = e^{e^{2} (e^{t} t - e^{t}) - t + c_{1}}

Solution steps

\frac{d N}{d t} + N = Nt e^{(t + 2)}

Solve separable ODE:

N = e^{e^{2} (e^{t} t - e^{t}) - t + c_{1}}

N = e^{e^{2} (e^{t} t - e^{t}) - t + c_{1}}

n = 1 \sum \infty \frac{n !}{2 n - 1}

y^{^{'}} = \frac{5}{y + 2}

\frac{d}{d x} ((5 x^{6} + 8 x^{3})^{4})

\int csc (3 x) cot (3 x) d x

\int (3 y^{2}) d y

What is the solution for (dN)/(dt)+N=Nte^{(t+2)} ?
The solution for (dN)/(dt)+N=Nte^{(t+2)} is N=e^{e^2(e^tt-e^t)-t+c_{1}}