y^'+xy=xy^{-2}

Lösung

y^{^{'}} + x y = x y^{- 2}

y = 3 - e^{- \frac{3 x ^{2}}{2} - c_{1}} + 1

Schritte zur Lösung

y^{'} (x) + x y = x y^{- 2}

Solve separable ODE:

y = 3 - e^{- \frac{3 x ^{2}}{2} - c_{1}} + 1

y = 3 - e^{- \frac{3 x ^{2}}{2} - c_{1}} + 1

\frac{d}{d x} (12 x - 3 x^{2})

ma c l a u r in \frac{1}{1 + 3 x}

\frac{d}{d x} (e^{2 x} - 1)

d er i v a t i v e ln (x)

2 y y^{^{'}} + 6 = y^{2} + 6 x