derivative f(x)=5x^4-6x^2+1

解答

导数

f (x) = 5 x^{4} - 6 x^{2} + 1

20 x^{3} - 12 x

求解步骤

\frac{d}{d x} (5 x^{4} - 6 x^{2} + 1)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{4}) - \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (5 x^{4}) = 20 x^{3}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (1) = 0

= 20 x^{3} - 12 x + 0

化简

= 20 x^{3} - 12 x

\frac{\partial}{\partial x} (2 x y - 3)

\frac{\partial}{\partial x} (\frac{4}{( x + 2 ) ^{2}})

t a y l or \frac{4}{x}, 3

t \to 1 lim (\frac{t ^{2} - 1}{t - 1})

\int_{1}^{b} \frac{1}{( x + 6 ) ^{2}} d x