y^{''}=9t^2

Lösung

y^{^{''}} = 9 t^{2}

y = \frac{3 t ^{4}}{4} + c_{1} t + c_{2}

Schritte zur Lösung

y^{''} (t) = 9 t^{2}

Löse

y^{''} (t) = 9 t^{2} : y^{'} (t) = 3 t^{3} + c_{1}

Löse

y^{'} (t) = 3 t^{3} + c_{1} : y = \frac{3 t ^{4}}{4} + c_{1} t + c_{2}

y = \frac{3 t ^{4}}{4} + c_{1} t + c_{2}

\int cos (n) π x d x

\int (π - x) d x

\int x + 9 d x

\int e^{- 3 x + 2} d x

\frac{\partial}{\partial x} ((x^{2}) (y^{3}))