integral of 2x+9x^{-2}

Lösung

\int 2 x + 9 x^{- 2} d x

x^{2} - \frac{9}{x} + C

Schritte zur Lösung

\int 2 x + 9 x^{- 2} d x

9 x^{- 2} = \frac{9}{x ^{2}}

= \int 2 x + \frac{9}{x ^{2}} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x d x + \int \frac{9}{x ^{2}} d x

\int 2 x d x = x^{2}

\int \frac{9}{x ^{2}} d x = - \frac{9}{x}

= x^{2} - \frac{9}{x}

Füge eine Konstante zur Lösung hinzu

= x^{2} - \frac{9}{x} + C

y^{^{'}} - \frac{1}{x} y = x^{2} y^{4}

t an g e n t f (x) = 3 x^{2} - 3 x - 5

\frac{\partial}{\partial y} (x^{4} y^{- 2})

\int \frac{1}{( a ^{2} - x ^{2} ) ^{\frac{3}{2}}} d x

\int_{a}^{2 a} a x - \frac{a ^{3}}{x} d x