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Beliebt Rechnen >

inverselaplace 1/((s+5)^2)

Lösung

inverse laplace transformation

\frac{1}{( s + 5 ) ^{2}}

Lösung

e^{- 5 t} t

Schritte zur Lösung

L^{- 1} {\frac{1}{( s + 5 ) ^{2}}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {F (s - a)} = e^{a t} f (t)

Für

\frac{1}{( s + 5 ) ^{2}} : a = - 5, F (s) = \frac{1}{s ^{2}}

= e^{- 5 t} L^{- 1} {\frac{1}{s ^{2}}}

L^{- 1} {\frac{1}{s ^{2}}} : t

= e^{- 5 t} t

Beliebte Beispiele

derivative of (2x^5+3x^4-x^3+2/(x^2))

\frac{d}{d x} (\frac{2 x ^{5} + 3 x ^{4} - x ^{3} + 2}{x ^{2}})

integral from 0 to 3 of 2x-1

\int_{0}^{3} 2 x - 1 d x

integral of 3/2 x^{1/2}

\int \frac{3}{2} x^{\frac{1}{2}} d x

limit as x approaches 1 of-2sqrt(1-x)+2

x \to 1 lim (- 2 1 - x + 2)

derivative of sin(x^2+2x)

\frac{d}{d x} (sin (x^{2} + 2 x))