laplacetransform 1/4*sin(2t)

Lösung

laplace transformation

\frac{1}{4} \cdot sin (2 t)

\frac{1}{2 ( s ^{2} + 4 )}

Schritte zur Lösung

L {\frac{1}{4} sin (2 t)}

Verwende die konstante Multiplikationseigenschaft der Laplace-Transformation:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= \frac{1}{4} L {sin (2 t)}

L {sin (2 t)} : \frac{2}{s ^{2} + 4}

= \frac{1}{4} \cdot \frac{2}{s ^{2} + 4}

Fasse

\frac{1}{4} \frac{2}{s ^{2} + 4}

zusammen:

\frac{1}{2 ( s ^{2} + 4 )}

= \frac{1}{2 ( s ^{2} + 4 )}

\frac{d}{d x} (\frac{e ^{x} x - e ^{x}}{7 x ^{2}})

\frac{\partial}{\partial y} (sin (x - y) + (x - y))

\frac{d}{d x} (x - 3 e^{x})

\frac{\partial}{\partial x} (ln (x^{2} + 3))

x \to 2 lim (\frac{2 x - 4}{x - 2})