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شائع حساب التفاضل والتكامل >

integral of sqrt(a-x^2)

الحلّ

\int a - x^{2} d x

الحلّ

\frac{1}{2} a (arcsin (\frac{1}{a} x) + \frac{1}{2} sin (2 arcsin (\frac{1}{a} x))) + C

خطوات الحلّ

\int a - x^{2} d x

a - x^{2} = a (1 - \frac{x ^{2}}{a})

= \int a (1 - \frac{x ^{2}}{a}) d x

\frac{a ^{n}}{b ^{n}} = (\frac{a}{b})^{n}

:فعّل قانون القوى

\frac{x ^{2}}{a} = (\frac{x}{a})^{2}

= \int a (1 - (\frac{x}{a})^{2}) d x

(\frac{x}{a})^{2} = \frac{x ^{2}}{a}

= \int a (1 - \frac{x ^{2}}{a}) d x

(a \cdot b)^{n} = a^{n} \cdot b^{n}

:فعّل قانون القوى

a (1 - \frac{x ^{2}}{a}) = a (1 - \frac{x ^{2}}{a})

= \int a 1 - \frac{x ^{2}}{a} d x

\int a \cdot f (x) d x = a \cdot \int f (x) d x

:قم بإخراج الثابت

= a \cdot \int 1 - \frac{x ^{2}}{a} d x

Apply Trigonometric Substitution

= a \cdot \int a cos^{2} (u) d u

\int a \cdot f (x) d x = a \cdot \int f (x) d x

:قم بإخراج الثابت

= a a \cdot \int cos^{2} (u) d u

Rewrite using trig identities

= a a \cdot \int \frac{1 + cos ( 2 u )}{2} d u

\int a \cdot f (x) d x = a \cdot \int f (x) d x

:قم بإخراج الثابت

= a a \frac{1}{2} \cdot \int 1 + cos (2 u) d u

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

:فعّل الميزة الخطيّة

= a a \frac{1}{2} (\int 1 d u + \int cos (2 u) d u)

\int 1 d u = u

\int cos (2 u) d u = \frac{1}{2} sin (2 u)

= a a \frac{1}{2} (u + \frac{1}{2} sin (2 u))

u = arcsin (\frac{1}{a} x)

استبدل مجددًا

= a a \frac{1}{2} (arcsin (\frac{1}{a} x) + \frac{1}{2} sin (2 arcsin (\frac{1}{a} x)))

a a = a

:فعْل قانون الجذور

a a = a

= \frac{1}{2} a (arcsin (\frac{1}{a} x) + \frac{1}{2} sin (2 arcsin (\frac{1}{a} x)))

أضف ثابت التكامل للحل

= \frac{1}{2} a (arcsin (\frac{1}{a} x) + \frac{1}{2} sin (2 arcsin (\frac{1}{a} x))) + C

رسم

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